Scott Haseley 153c0267b6 Changes to userland progress to tweak progress output for test161. We needed
more periodic progress in some cases due to the large slow down that happens
when swapping is implemented (ASST3.3).
2016-04-27 18:46:44 -04:00

108 lines
3.3 KiB
C

/*
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* The President and Fellows of Harvard College.
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*
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*/
/* matmult.c
* Test program to do matrix multiplication on large arrays.
*
* This version uses a storage-inefficient technique to get a
* shorter running time for the same memory usage.
*
* Intended to stress virtual memory system.
*
* Once the VM system assignment is complete your system should be
* able to survive this.
*/
#include <unistd.h>
#include <stdio.h>
#include <test161/test161.h>
#define Dim 72 /* sum total of the arrays doesn't fit in
* physical memory
*/
#define RIGHT 8772192 /* correct answer */
int A[Dim][Dim];
int B[Dim][Dim];
int C[Dim][Dim];
int T[Dim][Dim][Dim];
int
main(void)
{
int i, j, k, r;
for (i = 0; i < Dim; i++) { /* first initialize the matrices */
for (j = 0; j < Dim; j++) {
TEST161_LPROGRESS_N(i*Dim + j, 1000);
A[i][j] = i;
B[i][j] = j;
C[i][j] = 0;
}
}
nprintf("\n");
for (i = 0; i < Dim; i++) { /* then multiply them together */
for (j = 0; j < Dim; j++) {
for (k = 0; k < Dim; k++) {
TEST161_LPROGRESS_N(i*j*Dim*Dim + k, 50000);
T[i][j][k] = A[i][k] * B[k][j];
}
}
}
nprintf("\n");
for (i = 0; i < Dim; i++) {
for (j = 0; j < Dim; j++) {
for (k = 0; k < Dim; k++) {
TEST161_LPROGRESS_N(i*j*Dim*Dim + k, 50000);
C[i][j] += T[i][j][k];
}
}
}
nprintf("\n");
r = 0;
for (i = 0; i < Dim; i++)
r += C[i][i];
nprintf("matmult finished.\n");
nprintf("answer is: %d (should be %d)\n", r, RIGHT);
if (r != RIGHT) {
nprintf("FAILED\n");
success(TEST161_FAIL, SECRET, "/testbin/matmult");
return 1;
}
nprintf("Passed.\n");
success(TEST161_SUCCESS, SECRET, "/testbin/matmult");
return 0;
}